Ruby Challenge: Binary_mafs

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Task Details:

Execute the code against the input file (somefile.txt).
The expected output results are below.

15
57

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Input File Contents (somefile.txt):

0b1 0b10 0b11 0b100 0b101
0b1 0b11 0b111 0b1111 0b11111

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Binary_mafs Challenge Solution

for arg in ARGV
   file = File.open(arg)
   file_data = file.read
   array = []

   file_data.each_line do |line|
     array = line.strip.split

     array.each_with_index do |item ,index|
       array[index] = Integer(item)
     end
     
     puts array.sum
     array = []
   end
end

Solution Notes:

Initialize an array (array[]) to store the binary values in an ordered manner.
Use the each loop to conduct the operation for each line.

Array is populated with the binary values.
The .strip method to removes any new line whitespaces.
The .split method is also used to itemize the binary values into the array.

Modify the array items with the .each_with_index method.
It is used to carry over the item value as well as the index value to conduct the array modification.

The Integer() class used convert the binary values into integer values ready to summation.

The .sum method used to sum all the integers in the array.

The array[] code empties the array for the next iteration on the “each_line” loop.